Autosomal inheritance:-
Transmission of characters other than the sex
linked traits from parents to their offspring is autosomal inheritance.
Autosomes control variety of characters other than sex.
Such characters are called as autosome linked traits.
Autosomal inheritance can be either dominant type or recessive type.
A) widow’s peak:-
1) It is determined by autosomal dominant gene.
2) A prominent ‘V’ shaped hairline is seen on forehead.
3) It occurs in homozygous dominant condition (WW) or heterozygous condition
(Ww).
4) Homozygous recessive (ww) will never have widow’s peak.
5) Shows equal chances of expression in males and females.
B) Phenylketonuria:- (autosomal recessive trait)
A defective gene (genetic mutation) causes PKU, which can be mild, moderate or severe.
In a person with PKU, this defective gene causes a lack of or deficiency of the enzyme that's needed to process phenylalanine, an amino acid.
A dangerous buildup of phenylalanine can develop when a person with PKU eats protein-rich foods, such as milk, cheese, nuts or meat, and even grains such as bread and pasta, or eats aspartame, an artificial sweetener. This buildup of phenylalanine results in damage to nerve cells in the brain.
PKU signs and symptoms can be mild or severe and may include:
• A musty odor in the breath, skin or urine, caused by too much phenylalanine in the body
• Neurological problems that may include seizures
• Skin rashes (eczema)
• Fair skin and blue eyes, because phenylalanine can't transform into melanin — the pigment responsible for hair and skin tone
• Abnormally small head (microcephaly) Hyperactivity
• Intellectual disability Delayed development
• Behavioral, emotional and social problems
• Psychiatric disorders
Q.: What is sex linked genes? Explain its types in detail?
Ans.: 1) The genes located on non-homologous regions of sex chromosomes but involved in sex determination are called as sex linked genes.
2) The body characters controlled by sex linked genes are known as sex linked characters.
3) The phenomenon of inheritance of sex - linked genes is called as sex linked inheritance or sex linkage.
4) There are two types of sex linked genes.
A) X- linked genes / sex linked genes:
1) Genes located on non-homologous part of X - chromosome only are called as X - linked genes.
2) These genes show no corresponding allele on Y - chromosome.
3) The recessive sex linked genes in humans are responsible for sex linked characters like hemophilia, colour blindness, night blindness, myopia, muscular dystrophy etc.
4) Females shows two X-chromosomes and a single X-chromosomes is present in males.
Due to this reason two recessive sex linked genes are necessary for expression of recessive characters in female whereas a single recessive gene is sufficient to express recessive character in males.
5) If a female receives recessive gene over one X- chromosomes the dominant gene if present on other X- chromosomes will suppress its expression.
Such a female will never express recessive character.
6) The female with one recessive gene is called as carrier.
7) Very rarely any female individual will show both recessive genes on X- chromosomes.
8) Males suffer more from phenotypic expression of recessive sex linked gene as they don’t have homologous X-chromosomes or allelic pair on Y-chromosome.
9) Show criss - cross inheritance.
B) Y - linked genes / holandric genes:
1) The genes located over non homologous part of Y - chromosomes only are called as Y - linked genes.
2) They inherit along Y - chromosomes and are expressed only in males.
3) Excessive growth of hair on external ear or pinna i.e. Hypertrichoisis is an example.
Give reasons: Sex linked characters appear more frequently in men than in women.
Ans.: 1) Human male shows a pair of heteromorphic sex chromosome i.e. XY while a female shows homomorphic pair as XX.
2) Since, Y - chromosome is present in males only and not in females
Y-linked genes will be expressed only in males.
3) The sex linked dominant genes present on X-chromosome are expressed equally in both males and females. But sex linked recessive gene are expressed only when both chromosome show recessive genes.
4) Since male contain only one X- chromosome he requires only a single recessive gene for expression of sex linked gene.
Due to all above reasons, sex linked
characters appear more frequently in men than in women.
Q.: Write a note on colour blindness?
Ans.
-
1) The
sex linked disease in which a person is unable to distinguish between red and green
colour as both these appears him or her grey is known as red greed colour
blindness.
2) The
disease develops due to recessive X - linked genes over X - chromosome.
3) It
prevents formation of colour sensitive cells in the retina necessary for
distinction of red and green.
4) The
genes for normal vision (dominant) and colour blindness (recessive) are located
on non-homologous region of X -
chromosome and absent on Y - chromosomes.
5) If the gene for normal vision is represented
by XC and gene for colour blindness is Xc
then the genotypes of different individuals can be represented as.....
Sex Normal Colorblind Carrier
Male XCY XcY -
Female XCXC XcXc XCXc
6) The
disease show criss cross inheritance and can be explained as follows:
A) If
a colorblind man marries a woman with normal vision then all the offspring will
have normal vision.
Parent: Colorblind male X Normal Female
Genotype
XcY X
XCXC
Gamete Xc Y XC
Checker
Board:
Xc Y
XC XCXC XCY
Carrier
female Normal Male
XC XCXc XCY
Carrier
Female Normal Male
Result: 1) All offsprings with normal vision.
2)
All daughters with normal vision but carrier for disease.
3)
All sons with normal vision.
B) If a carrier female (XCXc) marries
a male with normal vision (XCY) then,
Parent: Normal Male X Carrier Female
Genotype XCY X XCXc
Gametes
Xx Y XC Xc
Checker Board :
XC Y
XCXC XCY
XC Normal female Normal Male
Xc XCXc XcY
Carrier
Female Colorblind Male
In
the above marriage four genotypically different offsprings will be obtained.
Result:
1) 75 % offsprings will have normal
vision and 25 % will be colorblind.
2) Among sons, 50 % will be normal
and 50 % will be colorblind.
3) Among
daughters 100% will be normal vision but 50% daughters will be carriers for
recessive gene.
4) From
above two example, it is clear that in colorblind father transmits his gene to
his grandson via daughter which is carrier.
The inheritance of characters from
father to his grandson through his daughter is called as crisscross inheritance
or digenic type of inheritance.
Q.: Explain hemophilia with suitable
example.
Ans.:
1) Hemophilia is hereditary blood disease in which blood clots slowly or fails
to clot.
2) The person which carries the
recessive gene for hemophilia has deficiency of clotting factors VIII or IV in
blood. So, minor injuries cause continuous bleeding. Hence the disease is also
called as bleeder’s disease.
3) The
genes for normal clotting (dominant) and the hemophilia (Recessive) are located
on non-homologous region of X- chromosome but their alleles are absent on Y -
chromosome.
4) If
the gene for normal clotting is XH and gene for hemophilia is Xh then the
different genotypes of different individuals can be denoted as follows -
Sex Normal Hemophilic Carrier
Male XHY XhY -
Female XhXh XhXh XHXh
5) The
inheritance can be studied as follows -
A) If
a hemophilic male (x h y) marries a females with normal clotting of blood
(XHXH) then all the offsprings will have normal clotting of blood.
Parent Hemophilic X Normal
Male Female
Genotype Xhy X XH XH
Gametes Xh Y XH XH
Fi.
Generation:
Xh Y
XHXh XHY
XH Carrier female Normal Male
XH
Xh XHY
XH Carrier female Normal Male
Result: 1)
All offspring will have normal blood clotting.
2) All sons will have normal blood clotting.
3) All daughters will be carrier with normal
blood clotting.
B) If
a carrier female (XHXh) marries a male with normal clotting (XHY), then,
Parent: Normal
Male X Carrier Female
Genotype : XH Y X XH Xh
Gametes: XH Y XH Xh
Checker
Board:
XHXH XHY
XH Normal Female Normal Male
XHXh XhY
Xh Carrier Female Hemophilic Male
Result:
1) Four different types of genotypes will be
obtained.
2) 75 % offsprings will show normal blood clotting
and 25 % will be hemophilic.
3) Among sons 50 % will be normal and 50 % will be
hemophilic.
4) Among daughters 50 % will be normal and 50 %
will be carrier with normal clotting.
5) Similar
to colorblindness, hemophilia also follows criss cross inheritance or digenic
inheritance.
REFER TABLES ON PAGE NO. 63 AND 64 STATE BOARD BOOK

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